Southwest Airlines WN6982 Flight Status Today

Domestic flight Southwest Airlines WN6982 takes off from Cleveland (CLE) United States to Denver (DEN) United States. It's operated by Southwest Airlines. The plane leaves Cleveland Hopkins International Airport at 14:00 America/New_York. The flight is expected to land at Denver International Airport at 15:05 America/Denver. The flight will last about 3 hours 5 minutes.

WN6982 - SWA6982 Southwest Airlines (WN)
CLE Cleveland United States
Flight CLE to DEN
DEN Denver United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 06-August-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 14:00
None B11
Arrival Denver International Airport
IATA: DENICAO: KDEN
Scheduled 15:05
None C34
WN6982 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 5 minutes
  • Flight Distance: 1934 kms / 1202 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: SWA6982
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Denver
  • Current Time in Cleveland: Sunday 2026-03-01 19:29 PM
  • Current Time in Denver: Sunday 2026-03-01 17:29 PM

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Southwest Airlines Flight WN6982 FAQs

What is the scheduled flight duration for Southwest Airlines WN6982 flight?

On average, nonstop flight takes 3 hour(s) 5 minutes, with the flight distance of 1934 km (1202 miles).

What type of aircraft is used for the Southwest Airlines WN6982 flight?

All Southwest Airlines WN6982 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.