Southwest Airlines WN6848 Flight Status Today

Domestic flight Southwest Airlines WN6848 takes off from Columbus (CMH) United States to Atlanta (ATL) United States. It's operated by Southwest Airlines. The plane leaves John Glenn Columbus International Airport at 10:35 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 12:05 America/New_York. The flight will last about 1 hours 26 minutes.

WN6848 - SWA6848 Southwest Airlines (WN)
CMH Columbus United States
Flight CMH to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-August-2021
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 10:35
None None
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 12:05
N None
WN6848 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 26 minutes
  • Flight Distance: 719 kms / 447 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737 Passenger
  • Callsign: SWA6848
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Sunday 2026-01-18 09:44 AM
  • Current Time in Atlanta: Sunday 2026-01-18 09:44 AM

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Southwest Airlines Flight WN6848 FAQs

What is the scheduled flight duration for Southwest Airlines WN6848 flight?

On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 719 km (447 miles).

What type of aircraft is used for the Southwest Airlines WN6848 flight?

All Southwest Airlines WN6848 flights are operated using Boeing 737 Passenger aircraft.

Which terminal the flight Southwest Airlines WN6848 is arriving at?

Flight Southwest Airlines WN6848 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal N.