Southwest Airlines WN6787 Flight Status Today

Domestic flight Southwest Airlines WN6787 takes off from Chicago (MDW) United States to Cleveland (CLE) United States. It's operated by Southwest Airlines. The plane leaves Chicago Midway International Airport at 11:00 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 13:10 America/New_York. The flight will last about 1 hours 10 minutes.

WN6787 - SWA6787 Southwest Airlines (WN)
MDW Chicago United States
Flight MDW to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-August-2021
Departure Chicago Midway International Airport
IATA: MDWICAO: KMDW
Scheduled 11:00
None B12
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 13:10
None B11
WN6787 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 494 kms / 307 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 175
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: SWA6787
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Chicago: Thursday 2026-01-01 17:50 PM
  • Current Time in Cleveland: Thursday 2026-01-01 18:50 PM

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Southwest Airlines Flight WN6787 FAQs

What is the scheduled flight duration for Southwest Airlines WN6787 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 494 km (307 miles).

What type of aircraft is used for the Southwest Airlines WN6787 flight?

All Southwest Airlines WN6787 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.