Southwest Airlines WN6749 Flight Status Today

Domestic flight Southwest Airlines WN6749 takes off from Cleveland (CLE) United States to Chicago (MDW) United States. It's operated by Southwest Airlines. The plane leaves Cleveland Hopkins International Airport at 17:35 America/New_York. The flight is expected to land at Chicago Midway International Airport at 17:45 America/Chicago. The flight will last about 1 hours 10 minutes.

WN6749 - SWA6749 Southwest Airlines (WN)
CLE Cleveland United States
Flight CLE to MDW
MDW Chicago United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-August-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:35
None B10
Arrival Chicago Midway International Airport
IATA: MDWICAO: KMDW
Scheduled 17:45
None B22
WN6749 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 494 kms / 307 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: SWA6749
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cleveland: Thursday 2026-01-01 21:00 PM
  • Current Time in Chicago: Thursday 2026-01-01 20:00 PM

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Southwest Airlines Flight WN6749 FAQs

What is the scheduled flight duration for Southwest Airlines WN6749 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 494 km (307 miles).

What type of aircraft is used for the Southwest Airlines WN6749 flight?

All Southwest Airlines WN6749 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.