Southwest Airlines WN5800 Flight Status Today

Domestic flight Southwest Airlines WN5800 takes off from Washington (DCA) United States to Oklahoma City (OKC) United States. It's operated by Southwest Airlines. The plane leaves Ronald Reagan National Airport at 16:45 America/New_York. The flight is expected to land at Will Rogers World Airport at 18:55 America/Chicago. The flight will last about 3 hours 10 minutes.

WN5800 - SWA5800 Southwest Airlines (WN)
DCA Washington United States
Flight DCA to OKC
OKC Oklahoma City United States
Contact Airlines It may not operate on the date requested
Departure Ronald Reagan National Airport
IATA: DCAICAO: KDCA
Scheduled 16:45
1 A2
Arrival Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 18:55
None 18
WN5800 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 10 minutes
  • Flight Distance: 1862 kms / 1157 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Thursday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: F-KECP1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Washington: Wednesday 2025-12-31 23:35 PM
  • Current Time in Oklahoma City: Wednesday 2025-12-31 22:35 PM

Flight routes similar to Southwest Airlines WN5800

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American Airlines AA4602
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Southwest Airlines Flight WN5800 FAQs

What is the scheduled flight duration for Southwest Airlines WN5800 flight?

On average, nonstop flight takes 3 hour(s) 10 minutes, with the flight distance of 1862 km (1157 miles).

What type of aircraft is used for the Southwest Airlines WN5800 flight?

All Southwest Airlines WN5800 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.

How many Southwest Airlines WN5800 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN5800 is operated on Thursday.