Southwest Airlines WN5458 Flight Status Today

Domestic flight Southwest Airlines WN5458 takes off from Orlando (MCO) United States to Indianapolis (IND) United States. It's operated by Southwest Airlines. The plane leaves Orlando International Airport at 06:55 America/New_York. The flight is expected to land at Indianapolis International Airport at 09:15 America/Indiana/Indianapolis. The flight will last about 2 hours 20 minutes.

WN5458 - SWA5458 Southwest Airlines (WN)
MCO Orlando United States
Flight MCO to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure Orlando International Airport
IATA: MCOICAO: KMCO
Scheduled 06:55
A 128
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 09:15
None B21
WN5458 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1333 kms / 828 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KFXE1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Orlando: Sunday 2026-02-08 08:17 AM
  • Current Time in Indianapolis: Sunday 2026-02-08 08:17 AM

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Southwest Airlines Flight WN5458 FAQs

What is the scheduled flight duration for Southwest Airlines WN5458 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1333 km (828 miles).

What type of aircraft is used for the Southwest Airlines WN5458 flight?

All Southwest Airlines WN5458 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Southwest Airlines WN5458 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN5458 is operated on Tuesday.