Southwest Airlines WN4887 Flight Status Today

Domestic flight Southwest Airlines WN4887 takes off from Omaha (OMA) United States to Houston (HOU) United States. It's operated by Southwest Airlines. The plane leaves Eppley Airfield at 14:05 America/Chicago. The flight is expected to land at William P. Hobby Airport at 16:30 America/Chicago. The flight will last about 2 hours 25 minutes.

WN4887 - SWA4887 Southwest Airlines (WN)
OMA Omaha United States
Flight OMA to HOU
HOU Houston United States
Contact Airlines It may not operate on the date requested
Departure Eppley Airfield
IATA: OMAICAO: KOMA
Scheduled 14:05
None None
Arrival William P. Hobby Airport
IATA: HOUICAO: KHOU
Scheduled 16:30
None 5
WN4887 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 25 minutes
  • Flight Distance: 1293 kms / 804 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KFLL2
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Omaha: Sunday 2026-01-11 18:50 PM
  • Current Time in Houston: Sunday 2026-01-11 18:50 PM

Southwest Airlines Flight WN4887 FAQs

What is the scheduled flight duration for Southwest Airlines WN4887 flight?

On average, nonstop flight takes 2 hour(s) 25 minutes, with the flight distance of 1293 km (804 miles).

What type of aircraft is used for the Southwest Airlines WN4887 flight?

All Southwest Airlines WN4887 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Southwest Airlines WN4887 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN4887 is operated on Tuesday.