Southwest Airlines WN4838 Flight Status

WN4838 - SWA4838 Southwest Airlines (WN)
DEN Denver United States
Flight DEN to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Denver International Airport
IATA: DENICAO: KDEN
Scheduled 12:40
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:25
None B11
WN4838 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 29 minutes
  • Flight Distance: 1934 kms / 1202 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: SWA4838
  • Departure Timezone: America/Denver
  • Arrival Timezone: America/New_York
  • Current Time in Denver: Monday 2025-12-08 19:51 PM
  • Current Time in Cleveland: Monday 2025-12-08 21:51 PM

Domestic flight Southwest Airlines WN4838 takes off from Denver (DEN) United States to Cleveland (CLE) United States. It's operated by Southwest Airlines. The plane leaves Denver International Airport at 12:40 America/Denver. The flight is expected to land at Cleveland Hopkins International Airport at 17:25 America/New_York. The flight will last about 2 hours 29 minutes.

Similar flight route from Denver (DEN) to Cleveland (CLE)

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Frontier Airlines F91944
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Frequently asked questions, answered

What is the scheduled flight duration for Southwest Airlines WN4838 flight?

On average, nonstop flight takes 2 hour(s) 29 minutes, with the flight distance of 1934 km (1202 miles).

What type of aircraft is used for the Southwest Airlines WN4838 flight?

All Southwest Airlines WN4838 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Southwest Airlines WN4838 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN4838 is operated on Tuesday.