Southwest Airlines WN4748 Flight Status Today

Domestic flight Southwest Airlines WN4748 takes off from Chicago (MDW) United States to Omaha (OMA) United States. It's operated by Southwest Airlines. The plane leaves Chicago Midway International Airport at 07:55 America/Chicago. The flight is expected to land at Eppley Airfield at 09:35 America/Chicago. The flight will last about 1 hours 40 minutes.

WN4748 - SWA4748 Southwest Airlines (WN)
MDW Chicago United States
Flight MDW to OMA
OMA Omaha United States
Contact Airlines It may not operate on the date requested
Departure Chicago Midway International Airport
IATA: MDWICAO: KMDW
Scheduled 07:55
None B10
Arrival Eppley Airfield
IATA: OMAICAO: KOMA
Scheduled 09:35
None B16
WN4748 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 40 minutes
  • Flight Distance: 683 kms / 424 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 175
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-700 Passenger (Scimitar Winglets)
  • Callsign: F-KSMO3
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Chicago: Friday 2026-03-20 05:47 AM
  • Current Time in Omaha: Friday 2026-03-20 05:47 AM

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Southwest Airlines Flight WN4748 FAQs

What is the scheduled flight duration for Southwest Airlines WN4748 flight?

On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 683 km (424 miles).

What type of aircraft is used for the Southwest Airlines WN4748 flight?

All Southwest Airlines WN4748 flights are operated using Boeing 737-700 Passenger (Scimitar Winglets) aircraft.

How many Southwest Airlines WN4748 flights are operated a week?

6 flights per week. The Flight Southwest Airlines WN4748 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.