Southwest Airlines WN4690 Flight Status Today

Domestic flight Southwest Airlines WN4690 takes off from Nashville (BNA) United States to Cleveland (CLE) United States. It's operated by Southwest Airlines. The plane leaves Nashville International Airport at 18:45 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 21:20 America/New_York. The flight will last about 1 hours 35 minutes.

WN4690 - SWA4690 Southwest Airlines (WN)
BNA Nashville United States
Flight BNA to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Nashville International Airport
IATA: BNAICAO: KBNA
Scheduled 18:45
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 21:20
None None
WN4690 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 721 kms / 448 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Thursday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-700 Passenger (Scimitar Winglets)
  • Callsign: F-KDUG2
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Nashville: Sunday 2026-02-08 03:01 AM
  • Current Time in Cleveland: Sunday 2026-02-08 04:01 AM

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Southwest Airlines Flight WN4690 FAQs

What is the scheduled flight duration for Southwest Airlines WN4690 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 721 km (448 miles).

What type of aircraft is used for the Southwest Airlines WN4690 flight?

All Southwest Airlines WN4690 flights are operated using Boeing 737-700 Passenger (Scimitar Winglets) aircraft.

How many Southwest Airlines WN4690 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN4690 is operated on Thursday.