Southwest Airlines WN4538 Flight Status Today

Domestic flight Southwest Airlines WN4538 takes off from Columbus (CMH) United States to Sarasota (SRQ) United States. It's operated by Southwest Airlines. The plane leaves John Glenn Columbus International Airport at 17:15 America/New_York. The flight is expected to land at Sarasota Bradenton International Airport at 19:45 America/New_York. The flight will last about 2 hours 30 minutes.

WN4538 - SWA4538 Southwest Airlines (WN)
CMH Columbus United States
Flight CMH to SRQ
SRQ Sarasota United States
Contact Airlines It may not operate on the date requested
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 17:15
None A6
Arrival Sarasota Bradenton International Airport
IATA: SRQICAO: KSRQ
Scheduled 19:45
None None
WN4538 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 30 minutes
  • Flight Distance: 1399 kms / 869 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 143
  • Freight capacity: 8.4 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: F-KSTL2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Monday 2026-03-23 23:19 PM
  • Current Time in Sarasota: Monday 2026-03-23 23:19 PM

Flight routes similar to Southwest Airlines WN4538

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Southwest Airlines Flight WN4538 FAQs

What is the scheduled flight duration for Southwest Airlines WN4538 flight?

On average, nonstop flight takes 2 hour(s) 30 minutes, with the flight distance of 1399 km (869 miles).

What type of aircraft is used for the Southwest Airlines WN4538 flight?

All Southwest Airlines WN4538 flights are operated using Boeing 737-800 Passenger aircraft.

How many Southwest Airlines WN4538 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN4538 is operated on Tuesday.