Southwest Airlines WN1643 flight status now

WN1643 - SWA1643 Southwest Airlines (WN)

CLE Cleveland United States

STL Saint Louis United States

Scheduled On time Estimated Depart in 2 hours, 12 minutes

Departure Cleveland Hopkins International Airport

IATA: CLEICAO: KCLE

Scheduled 18:15 17 November 2025

Estimated 18:26 17 November 2025

None B10

Arrival Lambert-St. Louis International Airport

IATA: STLICAO: KSTL

Scheduled 19:00 17 November 2025

2 None

WN1643 Detail

• Type: Domestic Flight
• Flight Duration: 1 hours 45 minutes
• Flight Distance: 786 kms / 488 miles

Airline

• Southwest Airlines
• IATA: WN
• ICAO: SWA
• Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday

Passenger Services

• Service type: Normal passenger
• Seats: 143
• Freight capacity: 8.4 tons
• Passenger classes: Economy, Premium Economy

More Detail

• Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
• Callsign: F-KFHU1

• Departure Timezone: America/New_York
• Arrival Timezone: America/Chicago

• Current Time in Cleveland: Monday 2025-11-17 16:14 PM
• Current Time in Saint Louis: Monday 2025-11-17 15:14 PM

Domestic flight Southwest Airlines WN1643 takes off from Cleveland (CLE) United States to Saint Louis (STL) United States. It's operated by Southwest Airlines. The plane leaves Cleveland Hopkins International Airport at 18:15 17 November 2025 America/New_York. The flight is expected to land at Lambert-St. Louis International Airport at 19:00 17 November 2025 America/Chicago. The flight will last about 1 hours 45 minutes.

Current Local Time in Cleveland Hopkins International Airport Monday, November 17, 2025 16:14

Similar flight route from Cleveland (CLE) to Saint Louis (STL)

Airline	Flight no	Departure	Arrival
	WN1974 Southwest Airlines	17/11/2025 08:15	1 hours 50 minutes 09:05
	WN5154 Southwest Airlines	17/11/2025 12:20	1 hours 30 minutes 12:50

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