FlexFlight W29060 Flight Status Today

Domestic flight FlexFlight W29060 takes off from Lucknow (LKO) India to Hyderabad (HYD) India. It's operated by FlexFlight. The plane leaves Chaudhary Charan Singh International Airport at 14:15 Asia/Kolkata. The flight is expected to land at Rajiv Gandhi International Airport at 16:15 Asia/Kolkata. The flight will last about 2 hours 0 minutes.

W29060 - FXT9060 FlexFlight (W2)
LKO Lucknow India
Flight LKO to HYD
HYD Hyderabad India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 14:15
2 None
Arrival Rajiv Gandhi International Airport
IATA: HYDICAO: VOHS
Scheduled 16:15
None None
W29060 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 0 minutes
  • Flight Distance: 1085 kms / 674 miles
Airline
  • FlexFlight
  • IATA: W2
  • ICAO: FXT
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Lucknow: Sunday 2026-01-18 18:40 PM
  • Current Time in Hyderabad: Sunday 2026-01-18 18:40 PM

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FlexFlight Flight W29060 FAQs

What is the scheduled flight duration for FlexFlight W29060 flight?

On average, nonstop flight takes 2 hour(s) 0 minutes, with the flight distance of 1085 km (674 miles).