FlexFlight W28508 Flight Status Today

Domestic flight FlexFlight W28508 takes off from Milan (MXP) Italy to Rome (FCO) Italy. It's operated by FlexFlight. The plane leaves Milano Malpensa Airport at 18:40 Europe/Rome. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 19:55 Europe/Rome. The flight will last about 1 hours 1 minutes.

W28508 - FXT8508 FlexFlight (W2)
MXP Milan Italy
Flight MXP to FCO
FCO Rome Italy
Contact Airlines It may not operate on the date requested
Departure Milano Malpensa Airport
IATA: MXPICAO: LIMC
Scheduled 18:40
None None
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 19:55
None None
W28508 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 1 minutes
  • Flight Distance: 512 kms / 318 miles
Airline
  • FlexFlight
  • IATA: W2
  • ICAO: FXT
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Milan: Monday 2025-12-29 15:30 PM
  • Current Time in Rome: Monday 2025-12-29 15:30 PM

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FlexFlight Flight W28508 FAQs

What is the scheduled flight duration for FlexFlight W28508 flight?

On average, nonstop flight takes 1 hour(s) 1 minutes, with the flight distance of 512 km (318 miles).

How many FlexFlight W28508 flights are operated a week?

1 flights per week. The Flight FlexFlight W28508 is operated on Friday.