FlexFlight W28448 Flight Status Today

International flight FlexFlight W28448 takes off from Swidnik (LUZ) Poland to Rome (FCO) Italy. It's operated by FlexFlight. The plane leaves Lublin Airport at 17:30 Europe/Warsaw. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 19:50 Europe/Rome. The flight will last about 2 hours 2 minutes.

W28448 - FXT8448 FlexFlight (W2)
LUZ Swidnik Poland
Flight LUZ to FCO
FCO Rome Italy
Contact Airlines It may not operate on the date requested
Departure Lublin Airport
IATA: LUZICAO: EPLB
Scheduled 17:30
None None
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 19:50
None None
W28448 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 2 minutes
  • Flight Distance: 1317 kms / 819 miles
Airline
  • FlexFlight
  • IATA: W2
  • ICAO: FXT
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: Europe/Warsaw
  • Arrival Timezone: Europe/Rome
  • Current Time in Swidnik: Monday 2026-01-19 04:36 AM
  • Current Time in Rome: Monday 2026-01-19 04:36 AM

Flight routes similar to FlexFlight W28448

Airline Flight no Departure Arrival
AeroItalia XZ2993
AeroItalia 		19/01/2026
17:30 		2 hours 2 minutes
19:50

FlexFlight Flight W28448 FAQs

What is the scheduled flight duration for FlexFlight W28448 flight?

On average, nonstop flight takes 2 hour(s) 2 minutes, with the flight distance of 1317 km (819 miles).

What type of aircraft is used for the FlexFlight W28448 flight?

All FlexFlight W28448 flights are operated using Airbus A320 aircraft.

How many FlexFlight W28448 flights are operated a week?

6 flights per week. The Flight FlexFlight W28448 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.