Virgin Atlantic VS4938 Flight Status Today

International flight Virgin Atlantic VS4938 takes off from New York (JFK) United States to Mexico City (MEX) Mexico. It's operated by Virgin Atlantic. The plane leaves John F. Kennedy International Airport at 16:10 America/New_York. The flight is expected to land at Benito Juarez International Airport at 20:35 America/Mexico_City. The flight will last about 2 hours 49 minutes.

VS4938 - VIR4938 Virgin Atlantic (VS)
JFK New York United States
Flight JFK to MEX
MEX Mexico City Mexico
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-January-2021
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 16:10
None C8
Arrival Benito Juarez International Airport
IATA: MEXICAO: MMMX
Scheduled 20:35
4 B47
VS4938 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 49 minutes
  • Flight Distance: 3363 kms / 2090 miles
Airline
  • Virgin Atlantic
  • IATA: VS
  • ICAO: VIR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Mexico_City
  • Current Time in New York: Tuesday 2026-02-10 10:11 AM
  • Current Time in Mexico City: Tuesday 2026-02-10 09:11 AM

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Virgin Atlantic Flight VS4938 FAQs

What is the scheduled flight duration for Virgin Atlantic VS4938 flight?

On average, nonstop flight takes 2 hour(s) 49 minutes, with the flight distance of 3363 km (2090 miles).

Which terminal the flight Virgin Atlantic VS4938 is arriving at?

Flight Virgin Atlantic VS4938 arrives in Benito Juarez International Airport at Terminal 4.