Virgin Atlantic VS4638 Flight Status Today

International flight Virgin Atlantic VS4638 takes off from New York (JFK) United States to Montego Bay (MBJ) Jamaica. It's operated by Virgin Atlantic. The plane leaves John F. Kennedy International Airport at 06:15 America/New_York. The flight is expected to land at Sangster International Airport at 09:15 America/Jamaica. The flight will last about 3 hours 42 minutes.

VS4638 - VIR4638 Virgin Atlantic (VS)
JFK New York United States
Flight JFK to MBJ
MBJ Montego Bay Jamaica
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 06:15
4 B38
Arrival Sangster International Airport
IATA: MBJICAO: MKJS
Scheduled 09:15
None 5
VS4638 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 42 minutes
  • Flight Distance: 2486 kms / 1545 miles
Airline
  • Virgin Atlantic
  • IATA: VS
  • ICAO: VIR
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A321 (sharklets)
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Jamaica
  • Current Time in New York: Friday 2026-02-27 19:38 PM
  • Current Time in Montego Bay: Friday 2026-02-27 19:38 PM

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Virgin Atlantic Flight VS4638 FAQs

What is the scheduled flight duration for Virgin Atlantic VS4638 flight?

On average, nonstop flight takes 3 hour(s) 42 minutes, with the flight distance of 2486 km (1545 miles).

What type of aircraft is used for the Virgin Atlantic VS4638 flight?

All Virgin Atlantic VS4638 flights are operated using Airbus A321 (sharklets) aircraft.

How many Virgin Atlantic VS4638 flights are operated a week?

1 flights per week. The Flight Virgin Atlantic VS4638 is operated on Friday.