Virgin Atlantic VS3938 Flight Status Today

International flight Virgin Atlantic VS3938 takes off from New York (JFK) United States to Amsterdam (AMS) Netherlands. It's operated by Virgin Atlantic. The plane leaves John F. Kennedy International Airport at 22:30 America/New_York. The flight is expected to land at Amsterdam Airport Schiphol at 12:10 Europe/Amsterdam. The flight will last about 7 hours 40 minutes.

VS3938 - VIR3938 Virgin Atlantic (VS)
JFK New York United States
Flight JFK to AMS
AMS Amsterdam Netherlands
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 22:30
4 B34
Arrival Amsterdam Airport Schiphol
IATA: AMSICAO: EHAM
Scheduled 12:10
None G3
VS3938 Detail
  • Type: International Flight
  • Flight Duration: 7 hours 40 minutes
  • Flight Distance: 5864 kms / 3644 miles
Airline
  • Virgin Atlantic
  • IATA: VS
  • ICAO: VIR
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 293
  • Freight capacity: 10 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A330-900neo
  • Callsign: VIR3938
  • Departure Timezone: America/New_York
  • Arrival Timezone: Europe/Amsterdam
  • Current Time in New York: Wednesday 2026-04-29 08:39 AM
  • Current Time in Amsterdam: Wednesday 2026-04-29 14:39 PM

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Virgin Atlantic Flight VS3938 FAQs

What is the scheduled flight duration for Virgin Atlantic VS3938 flight?

On average, nonstop flight takes 7 hour(s) 40 minutes, with the flight distance of 5864 km (3644 miles).

What type of aircraft is used for the Virgin Atlantic VS3938 flight?

All Virgin Atlantic VS3938 flights are operated using Airbus A330-900neo aircraft.

How many Virgin Atlantic VS3938 flights are operated a week?

7 flights per week. The Flight Virgin Atlantic VS3938 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .