Virgin Atlantic VS3927 Flight Status Today

International flight Virgin Atlantic VS3927 takes off from Amsterdam (AMS) Netherlands to New York (JFK) United States. It's operated by Virgin Atlantic. The plane leaves Amsterdam Airport Schiphol at 14:30 Europe/Amsterdam. The flight is expected to land at John F. Kennedy International Airport at 16:55 America/New_York. The flight will last about 8 hours 25 minutes.

VS3927 - VIR3927 Virgin Atlantic (VS)
AMS Amsterdam Netherlands
Flight AMS to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Amsterdam Airport Schiphol
IATA: AMSICAO: EHAM
Scheduled 14:30
2 E20
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 16:55
4 B41
VS3927 Detail
  • Type: International Flight
  • Flight Duration: 8 hours 25 minutes
  • Flight Distance: 5864 kms / 3644 miles
Airline
  • Virgin Atlantic
  • IATA: VS
  • ICAO: VIR
  • Operating Days: Friday
Passenger Services
  • Service type: Normal passenger
  • Seats: 293
  • Freight capacity: 10 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A330-900neo
  • Callsign: VIR3927
  • Departure Timezone: Europe/Amsterdam
  • Arrival Timezone: America/New_York
  • Current Time in Amsterdam: Monday 2025-12-29 09:59 AM
  • Current Time in New York: Monday 2025-12-29 03:59 AM

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Virgin Atlantic Flight VS3927 FAQs

What is the scheduled flight duration for Virgin Atlantic VS3927 flight?

On average, nonstop flight takes 8 hour(s) 25 minutes, with the flight distance of 5864 km (3644 miles).

What type of aircraft is used for the Virgin Atlantic VS3927 flight?

All Virgin Atlantic VS3927 flights are operated using Airbus A330-900neo aircraft.

Which terminal the flight Virgin Atlantic VS3927 is arriving at?

Flight Virgin Atlantic VS3927 arrives in John F. Kennedy International Airport at Terminal 4.

How many Virgin Atlantic VS3927 flights are operated a week?

1 flights per week. The Flight Virgin Atlantic VS3927 is operated on Friday.