Virgin Australia VA6409 Flight Status Today

Domestic flight Virgin Australia VA6409 takes off from Atlanta (ATL) United States to Columbus (CMH) United States. It's operated by Virgin Australia. The plane leaves Hartsfield-Jackson Atlanta International Airport at 08:31 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 10:00 America/New_York. The flight will last about 1 hours 4 minutes.

VA6409 - VOZ6409 Virgin Australia (VA)
ATL Atlanta United States
Flight ATL to CMH
CMH Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 20-September-2020
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 08:31
S B22
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 10:00
C C54
VA6409 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 4 minutes
  • Flight Distance: 719 kms / 447 miles
Airline
  • Virgin Australia
  • IATA: VA
  • ICAO: VOZ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 234
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Boeing737-900ER Winglets Scimitar
  • Callsign: VOZ6409
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Atlanta: Saturday 2026-02-07 21:23 PM
  • Current Time in Columbus: Saturday 2026-02-07 21:23 PM

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Frontier Airlines F92540
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Virgin Australia Flight VA6409 FAQs

What is the scheduled flight duration for Virgin Australia VA6409 flight?

On average, nonstop flight takes 1 hour(s) 4 minutes, with the flight distance of 719 km (447 miles).

What type of aircraft is used for the Virgin Australia VA6409 flight?

All Virgin Australia VA6409 flights are operated using Boeing737-900ER Winglets Scimitar aircraft.

Which terminal the flight Virgin Australia VA6409 is arriving at?

Flight Virgin Australia VA6409 arrives in John Glenn Columbus International Airport at Terminal C.