Virgin Australia VA6408 Flight Status Today

Domestic flight Virgin Australia VA6408 takes off from Atlanta (ATL) United States to Columbus (CMH) United States. It's operated by Virgin Australia. The plane leaves Hartsfield-Jackson Atlanta International Airport at 18:48 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 20:17 America/New_York. The flight will last about 3 hours 40 minutes.

VA6408 - VOZ6408 Virgin Australia (VA)
ATL Atlanta United States
Flight ATL to CMH
CMH Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 21-September-2020
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 18:48
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 20:17
S
VA6408 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 40 minutes
  • Flight Distance: 719 kms / 447 miles
Airline
  • Virgin Australia
  • IATA: VA
  • ICAO: VOZ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 234
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Airbus A321
  • Callsign: VOZ6408
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Atlanta: Saturday 2026-02-28 03:39 AM
  • Current Time in Columbus: Saturday 2026-02-28 03:39 AM

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Virgin Australia Flight VA6408 FAQs

What is the scheduled flight duration for Virgin Australia VA6408 flight?

On average, nonstop flight takes 3 hour(s) 40 minutes, with the flight distance of 719 km (447 miles).

What type of aircraft is used for the Virgin Australia VA6408 flight?

All Virgin Australia VA6408 flights are operated using Airbus A321 aircraft.

Which terminal the flight Virgin Australia VA6408 is arriving at?

Flight Virgin Australia VA6408 arrives in John Glenn Columbus International Airport at Terminal S.