easyJet U27802 Flight Status Today

International flight easyJet U27802 takes off from Venice (VCE) Italy to Amsterdam (AMS) Netherlands. It's operated by easyJet. The plane leaves Venice Marco Polo Airport at 16:20 Europe/Rome. The flight is expected to land at Amsterdam Airport Schiphol at 18:25 Europe/Amsterdam. The flight will last about 2 hours 5 minutes.

U27802 - EZY7802 easyJet (U2)
VCE Venice Italy
Flight VCE to AMS
AMS Amsterdam Netherlands
Contact Airlines It may not operate on the date requested
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 16:20
None None
Arrival Amsterdam Airport Schiphol
IATA: AMSICAO: EHAM
Scheduled 18:25
None None
U27802 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 5 minutes
  • Flight Distance: 938 kms / 583 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-LIMC2
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Amsterdam
  • Current Time in Venice: Sunday 2026-02-08 11:07 AM
  • Current Time in Amsterdam: Sunday 2026-02-08 11:07 AM

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Garuda Indonesia GA9497
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Xiamen Airlines MF9767
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Kenya Airways KQ1652
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easyJet Flight U27802 FAQs

What is the scheduled flight duration for easyJet U27802 flight?

On average, nonstop flight takes 2 hour(s) 5 minutes, with the flight distance of 938 km (583 miles).

What type of aircraft is used for the easyJet U27802 flight?

All easyJet U27802 flights are operated using Airbus A320 aircraft.

How many easyJet U27802 flights are operated a week?

1 flights per week. The Flight easyJet U27802 is operated on Thursday.