easyJet U24552 Flight Status Today

International flight easyJet U24552 takes off from Venice (VCE) Italy to Paris (CDG) France. It's operated by easyJet. The plane leaves Venice Marco Polo Airport at 16:50 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 18:45 Europe/Paris. The flight will last about 1 hours 59 minutes.

U24552 - EZY4552 easyJet (U2)
VCE Venice Italy
Flight VCE to CDG
CDG Paris France
Contact Airlines It may not operate on the date requested
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 16:50
None None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 18:45
2B None
U24552 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 59 minutes
  • Flight Distance: 835 kms / 519 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-LIPE4
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Venice: Monday 2026-01-19 00:27 AM
  • Current Time in Paris: Monday 2026-01-19 00:27 AM

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easyJet Flight U24552 FAQs

What is the scheduled flight duration for easyJet U24552 flight?

On average, nonstop flight takes 1 hour(s) 59 minutes, with the flight distance of 835 km (519 miles).

What type of aircraft is used for the easyJet U24552 flight?

All easyJet U24552 flights are operated using Airbus A320 aircraft.

Which terminal the flight easyJet U24552 is arriving at?

Flight easyJet U24552 arrives in Charles de Gaulle Airport at Terminal 2B.

How many easyJet U24552 flights are operated a week?

6 flights per week. The Flight easyJet U24552 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.