Check your Flight status online
easyJet U24238 Flight Status Today
International flight easyJet U24238 takes off from Rome (FCO) Italy to Paris (CDG) France. It's operated by easyJet. The plane leaves Leonardo da Vinci-Fiumicino Airport at 09:55 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 12:10 Europe/Paris. The flight will last about 3 hours 23 minutes.
U24238 - EZY4238
easyJet (U2)
FCO
Rome Italy
CDG
Paris France
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 13-September-2019
U24238 Detail
- Type: International Flight
- Flight Duration: 3 hours 23 minutes
- Flight Distance: 1101 kms / 684 miles
Airline
- easyJet
- IATA: U2
- ICAO: EZY
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: Europe/Rome
- Arrival Timezone: Europe/Paris
- Current Time in Rome: Monday 2025-12-29 19:17 PM
- Current Time in Paris: Monday 2025-12-29 19:17 PM
Flight routes similar to easyJet U24238
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
CZ7341 China Southern Airlines |
29/12/2025 21:25 |
2 hours 15 minutes 23:40 |
|
EY3013 Etihad Airways |
29/12/2025 21:25 |
2 hours 15 minutes 23:40 |
|
KQ3035 Kenya Airways |
29/12/2025 06:00 |
2 hours 5 minutes 08:15 |
|
G35167 Gol |
29/12/2025 18:25 |
2 hours 15 minutes 20:40 |
|
AM5814 Aeromexico |
29/12/2025 12:50 |
2 hours 15 minutes 15:00 |
|
KM2258 Air Malta |
29/12/2025 21:25 |
2 hours 15 minutes 23:40 |
|
MK9523 Air Mauritius |
29/12/2025 09:55 |
2 hours 12 minutes 12:10 |
|
|
MK9529 Air Mauritius |
29/12/2025 18:25 |
2 hours 15 minutes 20:40 |
easyJet Flight U24238 FAQs
What is the scheduled flight duration for easyJet U24238 flight?
On average, nonstop flight takes 3 hour(s) 23 minutes, with the flight distance of 1101 km (684 miles).