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easyJet U24238 Flight Status Today
International flight easyJet U24238 takes off from Rome (FCO) Italy to Paris (CDG) France. It's operated by easyJet. The plane leaves Leonardo da Vinci-Fiumicino Airport at 09:55 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 12:10 Europe/Paris. The flight will last about 3 hours 23 minutes.
U24238 - EZY4238
easyJet (U2)
FCO
Rome Italy
CDG
Paris France
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 13-September-2019
U24238 Detail
- Type: International Flight
- Flight Duration: 3 hours 23 minutes
- Flight Distance: 1101 kms / 684 miles
Airline
- easyJet
- IATA: U2
- ICAO: EZY
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: Europe/Rome
- Arrival Timezone: Europe/Paris
- Current Time in Rome: Monday 2025-12-29 18:34 PM
- Current Time in Paris: Monday 2025-12-29 18:34 PM
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MK9523 Air Mauritius |
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G35269 Gol |
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easyJet Flight U24238 FAQs
What is the scheduled flight duration for easyJet U24238 flight?
On average, nonstop flight takes 3 hour(s) 23 minutes, with the flight distance of 1101 km (684 miles).
