easyJet U24238 Flight Status Today

International flight easyJet U24238 takes off from Rome (FCO) Italy to Paris (CDG) France. It's operated by easyJet. The plane leaves Leonardo da Vinci-Fiumicino Airport at 09:55 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 12:10 Europe/Paris. The flight will last about 3 hours 23 minutes.

U24238 - EZY4238 easyJet (U2)
FCO Rome Italy
Flight FCO to CDG
CDG Paris France
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 13-September-2019
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 09:55
None None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 12:10
None None
U24238 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 23 minutes
  • Flight Distance: 1101 kms / 684 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Rome: Monday 2026-01-19 16:03 PM
  • Current Time in Paris: Monday 2026-01-19 16:03 PM

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easyJet Flight U24238 FAQs

What is the scheduled flight duration for easyJet U24238 flight?

On average, nonstop flight takes 3 hour(s) 23 minutes, with the flight distance of 1101 km (684 miles).