easyJet U24014 Flight Status Today

International flight easyJet U24014 takes off from Paris (CDG) France to Venice (VCE) Italy. It's operated by easyJet. The plane leaves Charles de Gaulle Airport at 17:55 Europe/Paris. The flight is expected to land at Venice Marco Polo Airport at 19:35 Europe/Rome. The flight will last about 1 hours 40 minutes.

U24014 - EZY4014 easyJet (U2)
CDG Paris France
Flight CDG to VCE
VCE Venice Italy
Contact Airlines It may not operate on the date requested
Departure Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 17:55
2B None
Arrival Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 19:35
None None
U24014 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 40 minutes
  • Flight Distance: 835 kms / 519 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-LIPU1
  • Departure Timezone: Europe/Paris
  • Arrival Timezone: Europe/Rome
  • Current Time in Paris: Friday 2026-05-01 10:57 AM
  • Current Time in Venice: Friday 2026-05-01 10:57 AM

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easyJet Flight U24014 FAQs

What is the scheduled flight duration for easyJet U24014 flight?

On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 835 km (519 miles).

What type of aircraft is used for the easyJet U24014 flight?

All easyJet U24014 flights are operated using Airbus A319 aircraft.

How many easyJet U24014 flights are operated a week?

1 flights per week. The Flight easyJet U24014 is operated on Friday.