easyJet U24005 Flight Status Today

International flight easyJet U24005 takes off from Venice (VCE) Italy to Paris (CDG) France. It's operated by easyJet. The plane leaves Venice Marco Polo Airport at 20:10 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 22:05 Europe/Paris. The flight will last about 1 hours 55 minutes.

U24005 - EZY4005 easyJet (U2)
VCE Venice Italy
Flight VCE to CDG
CDG Paris France
Contact Airlines It may not operate on the date requested
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 20:10
None None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 22:05
2B None
U24005 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 835 kms / 519 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-LFQG3
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Venice: Monday 2025-12-29 17:58 PM
  • Current Time in Paris: Monday 2025-12-29 17:58 PM

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easyJet Flight U24005 FAQs

What is the scheduled flight duration for easyJet U24005 flight?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 835 km (519 miles).

What type of aircraft is used for the easyJet U24005 flight?

All easyJet U24005 flights are operated using Airbus A319 aircraft.

Which terminal the flight easyJet U24005 is arriving at?

Flight easyJet U24005 arrives in Charles de Gaulle Airport at Terminal 2B.

How many easyJet U24005 flights are operated a week?

6 flights per week. The Flight easyJet U24005 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.