easyJet U23338 Flight Status Today

Domestic flight easyJet U23338 takes off from Catania (CTA) Italy to Venice (VCE) Italy. It's operated by easyJet. The plane leaves Catania-Fontanarossa Airport at 16:50 Europe/Rome. The flight is expected to land at Venice Marco Polo Airport at 18:35 Europe/Rome. The flight will last about 1 hours 25 minutes.

U23338 - EZY3338 easyJet (U2)
CTA Catania Italy
Flight CTA to VCE
VCE Venice Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 23-October-2020
Departure Catania-Fontanarossa Airport
IATA: CTAICAO: LICC
Scheduled 16:50
A
Arrival Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 18:35
D
U23338 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 25 minutes
  • Flight Distance: 920 kms / 572 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Catania: Monday 2026-01-19 02:13 AM
  • Current Time in Venice: Monday 2026-01-19 02:13 AM

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easyJet Flight U23338 FAQs

What is the scheduled flight duration for easyJet U23338 flight?

On average, nonstop flight takes 1 hour(s) 25 minutes, with the flight distance of 920 km (572 miles).

What type of aircraft is used for the easyJet U23338 flight?

All easyJet U23338 flights are operated using Airbus A319 aircraft.

Which terminal the flight easyJet U23338 is arriving at?

Flight easyJet U23338 arrives in Venice Marco Polo Airport at Terminal D.