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Saudia Airlines SV6986 Flight Status Today
Domestic flight Saudia Airlines SV6986 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Saudia Airlines. The plane leaves Cleveland Hopkins International Airport at 07:10 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 08:59 America/New_York. The flight will last about 1 hours 43 minutes.
SV6986 - SVA6986
Saudia Airlines (SV)
CLE
Cleveland United States
JFK
New York United States
Contact Airlines
It may not operate on the date requested
SV6986 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 43 minutes
- Flight Distance: 682 kms / 424 miles
Airline
- Saudia Airlines
- IATA: SV
- ICAO: SVA
- Operating Days: Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
- Callsign: None
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Cleveland: Monday 2026-01-19 01:39 AM
- Current Time in New York: Monday 2026-01-19 01:39 AM
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DL5008 Delta |
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Saudia Airlines Flight SV6986 FAQs
What is the scheduled flight duration for Saudia Airlines SV6986 flight?
On average, nonstop flight takes 1 hour(s) 43 minutes, with the flight distance of 682 km (424 miles).
What type of aircraft is used for the Saudia Airlines SV6986 flight?
All Saudia Airlines SV6986 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.
Which terminal the flight Saudia Airlines SV6986 is arriving at?
Flight Saudia Airlines SV6986 arrives in John F. Kennedy International Airport at Terminal 4.
How many Saudia Airlines SV6986 flights are operated a week?
1 flights per week. The Flight Saudia Airlines SV6986 is operated on Saturday.