Saudia Airlines SV6860 Flight Status Today

Domestic flight Saudia Airlines SV6860 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Saudia Airlines. The plane leaves Cleveland Hopkins International Airport at 07:11 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 08:59 America/New_York. The flight will last about 1 hours 59 minutes.

SV6860 - SVA6860 Saudia Airlines (SV)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 07:11
TERM A7
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 08:59
4 A14
SV6860 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 59 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Saudia Airlines
  • IATA: SV
  • ICAO: SVA
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2025-12-29 08:14 AM
  • Current Time in New York: Monday 2025-12-29 08:14 AM

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Saudia Airlines Flight SV6860 FAQs

What is the scheduled flight duration for Saudia Airlines SV6860 flight?

On average, nonstop flight takes 1 hour(s) 59 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Saudia Airlines SV6860 flight?

All Saudia Airlines SV6860 flights are operated using Embraer 175 aircraft.

Which terminal the flight Saudia Airlines SV6860 is arriving at?

Flight Saudia Airlines SV6860 arrives in John F. Kennedy International Airport at Terminal 4.

How many Saudia Airlines SV6860 flights are operated a week?

1 flights per week. The Flight Saudia Airlines SV6860 is operated on Tuesday.