Aeroflot SU3559 Flight Status Today

Domestic flight Aeroflot SU3559 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Aeroflot. The plane leaves Cleveland Hopkins International Airport at 11:36 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 13:19 America/New_York. The flight will last about 1 hours 51 minutes.

SU3559 - AFL3559 Aeroflot (SU)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-March-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 11:36
4 B48
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:19
4 None
SU3559 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 51 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Aeroflot
  • IATA: SU
  • ICAO: AFL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Canadair CRJ 900
  • Callsign: AFL3559
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-02-08 05:05 AM
  • Current Time in New York: Sunday 2026-02-08 05:05 AM

Flight routes similar to Aeroflot SU3559

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Korean Air KE7504
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KLM KL6750
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Aeroflot Flight SU3559 FAQs

What is the scheduled flight duration for Aeroflot SU3559 flight?

On average, nonstop flight takes 1 hour(s) 51 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Aeroflot SU3559 flight?

All Aeroflot SU3559 flights are operated using Canadair CRJ 900 aircraft.

Which terminal the flight Aeroflot SU3559 is arriving at?

Flight Aeroflot SU3559 arrives in John F. Kennedy International Airport at Terminal 4.