Aeroflot SU3461 Flight Status Today

Domestic flight Aeroflot SU3461 takes off from Jacksonville (JAX) United States to New York (JFK) United States. It's operated by Aeroflot. The plane leaves Jacksonville International Airport at 11:35 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 13:52 America/New_York. The flight will last about 1 hours 46 minutes.

SU3461 - AFL3461 Aeroflot (SU)
JAX Jacksonville United States
Flight JAX to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 15-December-2020
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 11:35
MAIN
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:52
SU3461 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 46 minutes
  • Flight Distance: 1333 kms / 828 miles
Airline
  • Aeroflot
  • IATA: SU
  • ICAO: AFL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 110
  • Freight capacity: 1 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: B712
  • Callsign: AFL3461
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Jacksonville: Sunday 2026-02-08 05:12 AM
  • Current Time in New York: Sunday 2026-02-08 05:12 AM

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Aeroflot Flight SU3461 FAQs

What is the scheduled flight duration for Aeroflot SU3461 flight?

On average, nonstop flight takes 1 hour(s) 46 minutes, with the flight distance of 1333 km (828 miles).

What type of aircraft is used for the Aeroflot SU3461 flight?

All Aeroflot SU3461 flights are operated using B712 aircraft.