Aeroflot SU3445 Flight Status Today

Domestic flight Aeroflot SU3445 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Aeroflot. The plane leaves Cleveland Hopkins International Airport at 17:37 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 19:30 America/New_York. The flight will last about 1 hours 40 minutes.

SU3445 - AFL3445 Aeroflot (SU)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-April-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:37
B06
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 19:30
4 B53
SU3445 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 40 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Aeroflot
  • IATA: SU
  • ICAO: AFL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: CRJ9
  • Callsign: AFL3445
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-02-08 08:42 AM
  • Current Time in New York: Sunday 2026-02-08 08:42 AM

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Aeroflot Flight SU3445 FAQs

What is the scheduled flight duration for Aeroflot SU3445 flight?

On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Aeroflot SU3445 flight?

All Aeroflot SU3445 flights are operated using CRJ9 aircraft.

Which terminal the flight Aeroflot SU3445 is arriving at?

Flight Aeroflot SU3445 arrives in John F. Kennedy International Airport at Terminal 4.