Brussels Airlines SN9648 Flight Status Today

International flight Brussels Airlines SN9648 takes off from New Orleans (MSY) United States to Toronto (YYZ) Canada. It's operated by Brussels Airlines. The plane leaves Louis Armstrong New Orleans International Airport at 11:10 America/Chicago. The flight is expected to land at Pearson International Airport at 15:02 America/Toronto. The flight will last about 2 hours 52 minutes.

SN9648 - BEL9648 Brussels Airlines (SN)
MSY New Orleans United States
Flight MSY to YYZ
YYZ Toronto Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-January-2020
Departure Louis Armstrong New Orleans International Airport
IATA: MSYICAO: KMSY
Scheduled 11:10
None None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 15:02
1 None
SN9648 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 52 minutes
  • Flight Distance: 1789 kms / 1111 miles
Airline
  • Brussels Airlines
  • IATA: SN
  • ICAO: BEL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: E175
  • Callsign: BEL9648
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Toronto
  • Current Time in New Orleans: Friday 2026-01-02 10:44 AM
  • Current Time in Toronto: Friday 2026-01-02 11:44 AM

Flight routes similar to Brussels Airlines SN9648

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Air Canada Rouge RV1710
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None

Brussels Airlines Flight SN9648 FAQs

What is the scheduled flight duration for Brussels Airlines SN9648 flight?

On average, nonstop flight takes 2 hour(s) 52 minutes, with the flight distance of 1789 km (1111 miles).

What type of aircraft is used for the Brussels Airlines SN9648 flight?

All Brussels Airlines SN9648 flights are operated using E175 aircraft.

Which terminal the flight Brussels Airlines SN9648 is arriving at?

Flight Brussels Airlines SN9648 arrives in Pearson International Airport at Terminal 1.