SpiceJet SG9488 Flight Status Today

Domestic flight SpiceJet SG9488 takes off from Kolkata (CCU) India to Bagdogra (IXB) India. It's operated by SpiceJet. The plane leaves Netaji Subhas Chandra Bose Airport at 16:15 Asia/Kolkata. The flight is expected to land at Bagdogra Airport at 17:35 Asia/Kolkata. The flight will last about 1 hours 20 minutes.

SG9488 - SEJ9488 SpiceJet (SG)
CCU Kolkata India
Flight CCU to IXB
IXB Bagdogra India
Contact Airlines It may not operate on the date requested
Departure Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 16:15
None 106
Arrival Bagdogra Airport
IATA: IXBICAO: VEBD
Scheduled 17:35
None None
SG9488 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 20 minutes
  • Flight Distance: 448 kms / 278 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-900 (winglets) Passenger/BBJ3
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kolkata: Wednesday 2026-02-11 23:29 PM
  • Current Time in Bagdogra: Wednesday 2026-02-11 23:29 PM

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SpiceJet Flight SG9488 FAQs

What is the scheduled flight duration for SpiceJet SG9488 flight?

On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 448 km (278 miles).

What type of aircraft is used for the SpiceJet SG9488 flight?

All SpiceJet SG9488 flights are operated using Boeing 737-900 (winglets) Passenger/BBJ3 aircraft.

How many SpiceJet SG9488 flights are operated a week?

1 flights per week. The Flight SpiceJet SG9488 is operated on Monday.