SpiceJet SG9448 Flight Status Today

Domestic flight SpiceJet SG9448 takes off from Delhi (DEL) India to Bagdogra (IXB) India. It's operated by SpiceJet. The plane leaves Indira Gandhi International Airport at 09:45 Asia/Kolkata. The flight is expected to land at Bagdogra Airport at 12:40 Asia/Kolkata. The flight will last about 2 hours 49 minutes.

SG9448 - SEJ9448 SpiceJet (SG)
DEL Delhi India
Flight DEL to IXB
IXB Bagdogra India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 02-July-2020
Departure Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 09:45
T1 D 163R
Arrival Bagdogra Airport
IATA: IXBICAO: VEBD
Scheduled 12:40
None None
SG9448 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 49 minutes
  • Flight Distance: 1127 kms / 700 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Delhi: Wednesday 2025-12-31 14:19 PM
  • Current Time in Bagdogra: Wednesday 2025-12-31 14:19 PM

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SpiceJet Flight SG9448 FAQs

What is the scheduled flight duration for SpiceJet SG9448 flight?

On average, nonstop flight takes 2 hour(s) 49 minutes, with the flight distance of 1127 km (700 miles).

What type of aircraft is used for the SpiceJet SG9448 flight?

All SpiceJet SG9448 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.