SpiceJet SG7490 Flight Status Today

Domestic flight SpiceJet SG7490 takes off from Kolkata (CCU) India to Delhi (DEL) India. It's operated by SpiceJet. The plane leaves Netaji Subhas Chandra Bose Airport at 17:00 Asia/Kolkata. The flight is expected to land at Indira Gandhi International Airport at 19:15 Asia/Kolkata. The flight will last about 1 hours 21 minutes.

SG7490 - SEJ7490 SpiceJet (SG)
CCU Kolkata India
Flight CCU to DEL
DEL Delhi India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-April-2021
Departure Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 17:00
None 11L
Arrival Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 19:15
None 231
SG7490 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 21 minutes
  • Flight Distance: 1313 kms / 816 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: SEJ7490
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kolkata: Monday 2025-12-29 08:34 AM
  • Current Time in Delhi: Monday 2025-12-29 08:34 AM

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SpiceJet Flight SG7490 FAQs

What is the scheduled flight duration for SpiceJet SG7490 flight?

On average, nonstop flight takes 1 hour(s) 21 minutes, with the flight distance of 1313 km (816 miles).

What type of aircraft is used for the SpiceJet SG7490 flight?

All SpiceJet SG7490 flights are operated using Boeing 737-800 Passenger aircraft.