SpiceJet SG7449 Flight Status Today

Domestic flight SpiceJet SG7449 takes off from Chennai (MAA) India to Delhi (DEL) India. It's operated by SpiceJet. The plane leaves Chennai Airport at 08:45 Asia/Kolkata. The flight is expected to land at Indira Gandhi International Airport at 11:45 Asia/Kolkata. The flight will last about 2 hours 41 minutes.

SG7449 - SEJ7449 SpiceJet (SG)
MAA Chennai India
Flight MAA to DEL
DEL Delhi India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-June-2021
Departure Chennai Airport
IATA: MAAICAO: VOMM
Scheduled 08:45
None 08
Arrival Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 11:45
None 240
SG7449 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 41 minutes
  • Flight Distance: 1753 kms / 1089 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737 Passenger
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Chennai: Monday 2025-12-29 13:32 PM
  • Current Time in Delhi: Monday 2025-12-29 13:32 PM

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SpiceJet Flight SG7449 FAQs

What is the scheduled flight duration for SpiceJet SG7449 flight?

On average, nonstop flight takes 2 hour(s) 41 minutes, with the flight distance of 1753 km (1089 miles).

What type of aircraft is used for the SpiceJet SG7449 flight?

All SpiceJet SG7449 flights are operated using Boeing 737 Passenger aircraft.