SpiceJet SG7448 Flight Status Today

Domestic flight SpiceJet SG7448 takes off from Delhi (DEL) India to Chennai (MAA) India. It's operated by SpiceJet. The plane leaves Indira Gandhi International Airport at 05:00 Asia/Kolkata. The flight is expected to land at Chennai Airport at 08:00 Asia/Kolkata. The flight will last about 2 hours 55 minutes.

SG7448 - SEJ7448 SpiceJet (SG)
DEL Delhi India
Flight DEL to MAA
MAA Chennai India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-June-2021
Departure Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 05:00
None 238
Arrival Chennai Airport
IATA: MAAICAO: VOMM
Scheduled 08:00
None None
SG7448 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 55 minutes
  • Flight Distance: 1753 kms / 1089 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Delhi: Thursday 2026-04-09 12:38 PM
  • Current Time in Chennai: Thursday 2026-04-09 12:38 PM

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SpiceJet Flight SG7448 FAQs

What is the scheduled flight duration for SpiceJet SG7448 flight?

On average, nonstop flight takes 2 hour(s) 55 minutes, with the flight distance of 1753 km (1089 miles).

What type of aircraft is used for the SpiceJet SG7448 flight?

All SpiceJet SG7448 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.