SpiceJet SG7348 Flight Status Today

Domestic flight SpiceJet SG7348 takes off from Delhi (DEL) India to Kolkata (CCU) India. It's operated by SpiceJet. The plane leaves Indira Gandhi International Airport at 23:40 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 01:55 Asia/Kolkata. The flight will last about 2 hours 15 minutes.

SG7348 - SEJ7348 SpiceJet (SG)
DEL Delhi India
Flight DEL to CCU
CCU Kolkata India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-September-2020
Departure Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 23:40
None 127
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 01:55
None C4
SG7348 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 15 minutes
  • Flight Distance: 1313 kms / 816 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
  • Callsign: SEJ7348
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Delhi: Wednesday 2025-12-31 11:53 AM
  • Current Time in Kolkata: Wednesday 2025-12-31 11:53 AM

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SpiceJet Flight SG7348 FAQs

What is the scheduled flight duration for SpiceJet SG7348 flight?

On average, nonstop flight takes 2 hour(s) 15 minutes, with the flight distance of 1313 km (816 miles).

What type of aircraft is used for the SpiceJet SG7348 flight?

All SpiceJet SG7348 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.