SpiceJet SG7148 Flight Status Today

Domestic flight SpiceJet SG7148 takes off from Delhi (DEL) India to Kolkata (CCU) India. It's operated by SpiceJet. The plane leaves Indira Gandhi International Airport at 11:45 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 14:00 Asia/Kolkata. The flight will last about 2 hours 5 minutes.

SG7148 - SEJ7148 SpiceJet (SG)
DEL Delhi India
Flight DEL to CCU
CCU Kolkata India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-February-2021
Departure Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 11:45
None 230
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 14:00
None 11R
SG7148 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 5 minutes
  • Flight Distance: 1313 kms / 816 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: SEJ7148
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Delhi: Sunday 2026-04-12 22:10 PM
  • Current Time in Kolkata: Sunday 2026-04-12 22:10 PM

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SpiceJet Flight SG7148 FAQs

What is the scheduled flight duration for SpiceJet SG7148 flight?

On average, nonstop flight takes 2 hour(s) 5 minutes, with the flight distance of 1313 km (816 miles).

What type of aircraft is used for the SpiceJet SG7148 flight?

All SpiceJet SG7148 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.