SpiceJet SG4910 Flight Status Today

International flight SpiceJet SG4910 takes off from Riyadh (RUH) Saudi Arabia to Lucknow (LKO) India. It's operated by SpiceJet. The plane leaves King Khaled International Airport at 13:40 Asia/Riyadh. The flight is expected to land at Chaudhary Charan Singh International Airport at 20:40 Asia/Kolkata. The flight will last about 4 hours 25 minutes.

SG4910 - SEJ4910 SpiceJet (SG)
RUH Riyadh Saudi Arabia
Flight RUH to LKO
LKO Lucknow India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-February-2022
Departure King Khaled International Airport
IATA: RUHICAO: OERK
Scheduled 13:40
None None
Arrival Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 20:40
None None
SG4910 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 25 minutes
  • Flight Distance: 3422 kms / 2126 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: SEJ4910
  • Departure Timezone: Asia/Riyadh
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Riyadh: Friday 2026-01-02 02:03 AM
  • Current Time in Lucknow: Friday 2026-01-02 04:33 AM

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SpiceJet Flight SG4910 FAQs

What is the scheduled flight duration for SpiceJet SG4910 flight?

On average, nonstop flight takes 4 hour(s) 25 minutes, with the flight distance of 3422 km (2126 miles).

What type of aircraft is used for the SpiceJet SG4910 flight?

All SpiceJet SG4910 flights are operated using Boeing 737-800 Passenger aircraft.