SpiceJet SG482 Flight Status Today

Domestic flight SpiceJet SG482 takes off from Guwahati (GAU) India to Bagdogra (IXB) India. It's operated by SpiceJet. The plane leaves Lokpriya Gopinath Bordoloi International Airport at 09:15 Asia/Kolkata. The flight is expected to land at Bagdogra Airport at 10:05 Asia/Kolkata. The flight will last about 1 hours 21 minutes.

SG482 - SEJ482 SpiceJet (SG)
GAU Guwahati India
Flight GAU to IXB
IXB Bagdogra India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-October-2020
Departure Lokpriya Gopinath Bordoloi International Airport
IATA: GAUICAO: VEGT
Scheduled 09:15
None 23
Arrival Bagdogra Airport
IATA: IXBICAO: VEBD
Scheduled 10:05
None 55L
SG482 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 21 minutes
  • Flight Distance: 332 kms / 206 miles
Airline
  • SpiceJet
  • IATA: SG
  • ICAO: SEJ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-900 Passenger
  • Callsign: SEJ482
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Guwahati: Monday 2026-01-19 15:22 PM
  • Current Time in Bagdogra: Monday 2026-01-19 15:22 PM

Flight routes similar to SpiceJet SG482

Airline Flight no Departure Arrival
SpiceJet SG487
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IndiGo 6E3419
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None
17:15

SpiceJet Flight SG482 FAQs

What is the scheduled flight duration for SpiceJet SG482 flight?

On average, nonstop flight takes 1 hour(s) 21 minutes, with the flight distance of 332 km (206 miles).

What type of aircraft is used for the SpiceJet SG482 flight?

All SpiceJet SG482 flights are operated using Boeing 737-900 Passenger aircraft.