Royal Jordanian RJ7873 Flight Status Today

Domestic flight Royal Jordanian RJ7873 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by Royal Jordanian. The plane leaves John F. Kennedy International Airport at 20:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 22:10 America/New_York. The flight will last about 2 hours 8 minutes.

RJ7873 - RJA7873 Royal Jordanian (RJ)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:00
8 39
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 22:10
None C10
RJ7873 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 8 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Royal Jordanian
  • IATA: RJ
  • ICAO: RJA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-02-28 09:45 AM
  • Current Time in Cleveland: Saturday 2026-02-28 09:45 AM

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Royal Jordanian Flight RJ7873 FAQs

What is the scheduled flight duration for Royal Jordanian RJ7873 flight?

On average, nonstop flight takes 2 hour(s) 8 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Royal Jordanian RJ7873 flight?

All Royal Jordanian RJ7873 flights are operated using Embraer 175 aircraft.

How many Royal Jordanian RJ7873 flights are operated a week?

7 flights per week. The Flight Royal Jordanian RJ7873 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .