Jazz QK8538 Flight Status Today

International flight Jazz QK8538 takes off from Cleveland (CLE) United States to Toronto (YYZ) Canada. It's operated by Jazz. The plane leaves Cleveland Hopkins International Airport at 06:30 America/New_York. The flight is expected to land at Pearson International Airport at 07:38 America/Toronto. The flight will last about 1 hours 8 minutes.

QK8538 - JZA8538 Jazz (QK)
CLE Cleveland United States
Flight CLE to YYZ
YYZ Toronto Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-March-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 06:30
None None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 07:38
1 None
QK8538 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 8 minutes
  • Flight Distance: 312 kms / 194 miles
Airline
  • Jazz
  • IATA: QK
  • ICAO: JZA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Toronto
  • Current Time in Cleveland: Monday 2026-01-19 02:37 AM
  • Current Time in Toronto: Monday 2026-01-19 02:37 AM

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Lufthansa LH6615
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Air Canada AC8734
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Air Canada AC1110
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12:13
Air Canada AC8730
Air Canada 		19/01/2026
07:00 		0 minutes
08:03

Jazz Flight QK8538 FAQs

What is the scheduled flight duration for Jazz QK8538 flight?

On average, nonstop flight takes 1 hour(s) 8 minutes, with the flight distance of 312 km (194 miles).

Which terminal the flight Jazz QK8538 is arriving at?

Flight Jazz QK8538 arrives in Pearson International Airport at Terminal 1.