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Jazz QK289 Flight Status Today
Domestic flight Jazz QK289 takes off from Sudbury (YSB) Canada to Timmins (YTS) Canada. It's operated by Jazz. The plane leaves Sudbury Airport at 20:30 America/Toronto. The flight is expected to land at Timmins Victor M. Power Airport at 21:07 America/Toronto. The flight will last about 1 hours 12 minutes.
QK289 - JZA289
Jazz (QK)
YSB
Sudbury Canada
YTS
Timmins Canada
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 05-November-2020
QK289 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 12 minutes
- Flight Distance: 220 kms / 137 miles
Airline
- Jazz
- IATA: QK
- ICAO: JZA
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Toronto
- Arrival Timezone: America/Toronto
- Current Time in Sudbury: Wednesday 2026-01-21 21:00 PM
- Current Time in Timmins: Wednesday 2026-01-21 21:00 PM
Jazz Flight QK289 FAQs
What is the scheduled flight duration for Jazz QK289 flight?
On average, nonstop flight takes 1 hour(s) 12 minutes, with the flight distance of 220 km (137 miles).
