Pionair Australia PH284 Flight Status Today

Domestic flight Pionair Australia PH284 takes off from Cleveland (CLE) United States to Tampa (TPA) United States. It's operated by Pionair Australia. The plane leaves Cleveland Hopkins International Airport at 08:40 America/New_York. The flight is expected to land at Tampa International Airport at 11:13 America/New_York. The flight will last about 1 hours 24 minutes.

PH284 - SFZ284 Pionair Australia (PH)
CLE Cleveland United States
Flight CLE to TPA
TPA Tampa United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 08-May-2023
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 08:40
None None
Arrival Tampa International Airport
IATA: TPAICAO: KTPA
Scheduled 11:13
None None
PH284 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 24 minutes
  • Flight Distance: 1491 kms / 927 miles
Airline
  • Pionair Australia
  • IATA: PH
  • ICAO: SFZ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Learjet 35A
  • Callsign: GRB284
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2025-12-28 12:14 PM
  • Current Time in Tampa: Sunday 2025-12-28 12:14 PM

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Pionair Australia Flight PH284 FAQs

What is the scheduled flight duration for Pionair Australia PH284 flight?

On average, nonstop flight takes 1 hour(s) 24 minutes, with the flight distance of 1491 km (927 miles).

What type of aircraft is used for the Pionair Australia PH284 flight?

All Pionair Australia PH284 flights are operated using Learjet 35A aircraft.