Bangkok Airways PG9908 Flight Status Today

International flight Bangkok Airways PG9908 takes off from Ho Chi Minh City (SGN) Viet Nam to Bangkok (BKK) Thailand. It's operated by Bangkok Airways. The plane leaves Tan Son Nhat International Airport at 17:13 Asia/Ho_Chi_Minh. The flight is expected to land at Suvarnabhumi Airport at None Asia/Bangkok. The flight will last about 1 hours 41 minutes.

PG9908 - BKP9908 Bangkok Airways (PG)
SGN Ho Chi Minh City Viet Nam
Flight SGN to BKK
BKK Bangkok Thailand
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Tan Son Nhat International Airport
IATA: SGNICAO: VVTS
Scheduled 17:13
None None
Arrival Suvarnabhumi Airport
IATA: BKKICAO: VTBS
Scheduled None
None None
PG9908 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 718 kms / 446 miles
Airline
  • Bangkok Airways
  • IATA: PG
  • ICAO: BKP
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: ATR 72-600
  • Callsign: BKP9908
  • Departure Timezone: Asia/Ho_Chi_Minh
  • Arrival Timezone: Asia/Bangkok
  • Current Time in Ho Chi Minh City: Wednesday 2026-01-21 01:35 AM
  • Current Time in Bangkok: Wednesday 2026-01-21 01:35 AM

Flight routes similar to Bangkok Airways PG9908

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Vietnam Airlines VN601
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KLM KL3086
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FlexFlight W24805
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Cambodia Angkor Air K63605
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11:35 		1 hours 26 minutes
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VietJet Air VJ803
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Kenya Airways KQ5302
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Bangkok Airways Flight PG9908 FAQs

What is the scheduled flight duration for Bangkok Airways PG9908 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 718 km (446 miles).

What type of aircraft is used for the Bangkok Airways PG9908 flight?

All Bangkok Airways PG9908 flights are operated using ATR 72-600 aircraft.