Asiana Airlines OZ6474 Flight Status Today

Domestic flight Asiana Airlines OZ6474 takes off from Chicago (ORD) United States to Cleveland (CLE) United States. It's operated by Asiana Airlines. The plane leaves O'Hare International Airport at 09:00 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 11:23 America/New_York. The flight will last about 1 hours 21 minutes.

OZ6474 - AAR6474 Asiana Airlines (OZ)
ORD Chicago United States
Flight ORD to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-October-2019
Departure O'Hare International Airport
IATA: ORDICAO: KORD
Scheduled 09:00
1 C15
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 11:23
None C22
OZ6474 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 21 minutes
  • Flight Distance: 509 kms / 316 miles
Airline
  • Asiana Airlines
  • IATA: OZ
  • ICAO: AAR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 167
  • Freight capacity: 17.1 tons
  • Passenger classes: First Class, Economy, Shuttle
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: AAR6474
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Chicago: Thursday 2026-04-09 19:37 PM
  • Current Time in Cleveland: Thursday 2026-04-09 20:37 PM

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Asiana Airlines Flight OZ6474 FAQs

What is the scheduled flight duration for Asiana Airlines OZ6474 flight?

On average, nonstop flight takes 1 hour(s) 21 minutes, with the flight distance of 509 km (316 miles).

What type of aircraft is used for the Asiana Airlines OZ6474 flight?

All Asiana Airlines OZ6474 flights are operated using Boeing 737-800 Passenger aircraft.