Asiana Airlines OZ6459 Flight Status Today

Domestic flight Asiana Airlines OZ6459 takes off from Cleveland (CLE) United States to Chicago (ORD) United States. It's operated by Asiana Airlines. The plane leaves Cleveland Hopkins International Airport at 19:36 America/New_York. The flight is expected to land at O'Hare International Airport at 20:12 America/Chicago. The flight will last about 1 hours 36 minutes.

OZ6459 - AAR6459 Asiana Airlines (OZ)
CLE Cleveland United States
Flight CLE to ORD
ORD Chicago United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-October-2019
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 19:36
None C26
Arrival O'Hare International Airport
IATA: ORDICAO: KORD
Scheduled 20:12
1 C23
OZ6459 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 509 kms / 316 miles
Airline
  • Asiana Airlines
  • IATA: OZ
  • ICAO: AAR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 114
  • Freight capacity: 9.6 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: Boeing 737 Passenger
  • Callsign: AAR6459
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cleveland: Sunday 2026-01-18 09:30 AM
  • Current Time in Chicago: Sunday 2026-01-18 08:30 AM

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Asiana Airlines Flight OZ6459 FAQs

What is the scheduled flight duration for Asiana Airlines OZ6459 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 509 km (316 miles).

What type of aircraft is used for the Asiana Airlines OZ6459 flight?

All Asiana Airlines OZ6459 flights are operated using Boeing 737 Passenger aircraft.

Which terminal the flight Asiana Airlines OZ6459 is arriving at?

Flight Asiana Airlines OZ6459 arrives in O'Hare International Airport at Terminal 1.