PSA Airlines OH9948 Flight Status Today

Domestic flight PSA Airlines OH9948 takes off from Greenville (GSP) United States to Charlotte (CLT) United States. It's operated by PSA Airlines. The plane leaves Greenville-Spartanburg International Airport at 13:00 America/New_York. The flight is expected to land at Charlotte Douglas International Airport at 14:15 America/New_York. The flight will last about 1 hours 15 minutes.

OH9948 - JIA9948 PSA Airlines (OH)
GSP Greenville United States
Flight GSP to CLT
CLT Charlotte United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 06-December-2021
Departure Greenville-Spartanburg International Airport
IATA: GSPICAO: KGSP
Scheduled 13:00
None None
Arrival Charlotte Douglas International Airport
IATA: CLTICAO: KCLT
Scheduled 14:15
None None
OH9948 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 15 minutes
  • Flight Distance: 122 kms / 76 miles
Airline
  • PSA Airlines
  • IATA: OH
  • ICAO: JIA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Greenville: Friday 2026-04-10 13:42 PM
  • Current Time in Charlotte: Friday 2026-04-10 13:42 PM

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PSA Airlines Flight OH9948 FAQs

What is the scheduled flight duration for PSA Airlines OH9948 flight?

On average, nonstop flight takes 1 hour(s) 15 minutes, with the flight distance of 122 km (76 miles).

What type of aircraft is used for the PSA Airlines OH9948 flight?

All PSA Airlines OH9948 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.